Asked by roger
What is the axis of symmetry in -7/x^2-4
Answers
Answered by
Damon
I guess you probably mean
y = -7/ (x^2-4)
if x = 0 , y = -7/-4
if x = 1 , y = -7/-3
if x = -1, y = -7/-3
if x = 2, y = -7/0
if x = -2 y = -7/0
if x = 3, y = -7/5
if x = -3, y = -7/5
same left and right of x = 0 :)
y = -7/ (x^2-4)
if x = 0 , y = -7/-4
if x = 1 , y = -7/-3
if x = -1, y = -7/-3
if x = 2, y = -7/0
if x = -2 y = -7/0
if x = 3, y = -7/5
if x = -3, y = -7/5
same left and right of x = 0 :)
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