Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry). y=-x^2-2x

3 answers

find the x-intercepts. y=x^2+4x
looks like you are asking 2 separate questions

for the first :
why not pick integer values of x from -4 to +4 then plot those points.
That should give you a good idea what kind of parabola you have.
That should also give you a good idea where the vertex is.
Remember the axis of symmetry goes through the vertex.

for the second :

doesn't y = x^2 + 4x factor to

y = x(x+4) ?

Can you see what values of x would make the y equal to zero?
-4 is the answer? i think because i an only 10 and in year 6
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