Asked by mary
Identify the axis of symmetry, create a suitable table of values, then sketch the graph (including the axis of symmetry). y=-x^2-2x
Answers
Answered by
mary
find the x-intercepts. y=x^2+4x
Answered by
Reiny
looks like you are asking 2 separate questions
for the first :
why not pick integer values of x from -4 to +4 then plot those points.
That should give you a good idea what kind of parabola you have.
That should also give you a good idea where the vertex is.
Remember the axis of symmetry goes through the vertex.
for the second :
doesn't y = x^2 + 4x factor to
y = x(x+4) ?
Can you see what values of x would make the y equal to zero?
for the first :
why not pick integer values of x from -4 to +4 then plot those points.
That should give you a good idea what kind of parabola you have.
That should also give you a good idea where the vertex is.
Remember the axis of symmetry goes through the vertex.
for the second :
doesn't y = x^2 + 4x factor to
y = x(x+4) ?
Can you see what values of x would make the y equal to zero?
Answered by
dana
-4 is the answer? i think because i an only 10 and in year 6
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