What is the axis of symmetry, Vertex point, y intercept, and x intercept and the mirror of the y intercept of y=x2+6x+8

Answer 1

Help!! Change y-5= -2(x+3) into y=mx+b form:

Answer 2

in y = ax^2 + bx + c
the x of the vertex is -b/(2a)
for y = x^2 + 6x + 8
the x of the vertex is -6/2 = -3
and its y = 9 + 6(-3) + 8 = -1

so the vertex is (-3,-1)
the axis of symmetry is the vertical line passing through
the vertex, or y = -3

y-intercept, let x = 0 , so y = 8
x-intercept, let y = 0
x^2 + 6x + 8 = 0
(x+2)(x+4) = 0
x = -2, x = -4

(notice that the x of the vertex lies half way between the x-intercepts, that
would be another way to find the vertex.
You could also complete the square)

Don't know what you mean by the "mirror of the y-intercept"
We have to know who the mirror is, if it is the x-axis , then you would
have (0,-8).
I fail to see of what importance that would be.

2nd question: Change y-5= -2(x+3) into y=mx+b form
really?
Just expand the right side, then add 5 to both sides.
Simplify the right side