Asked by Melany
A radioactive substance decays in such a way that the amount of mass remaining after t days is given by the function
m(t) = 9e−0.012t
where m(t) is measured in kilograms.
(a) Find the mass at time t = 0.
m(t) = 9e−0.012t
where m(t) is measured in kilograms.
(a) Find the mass at time t = 0.
Answers
Answered by
Reiny
I am sure you meant:
m(t) = 9 e^(-.012t)
so if t = 0 , remember that anything^0 = 1
so m(0) = 9
m(t) = 9 e^(-.012t)
so if t = 0 , remember that anything^0 = 1
so m(0) = 9
Answered by
Melany
ALSO How much of the mass remains after 49 days? (Round your answer to one decimal place.) what would this look like just to double check?
Answered by
Damon
well, I suppose I will try although really I am sure you could try first.
9 e^-(.012*49)
= 9/(e^.588)
= 9/1.8
= 5
9 e^-(.012*49)
= 9/(e^.588)
= 9/1.8
= 5
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