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a radioactive substance decays 10% in 5 days. The amount remains after 20 days?
11 years ago

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DrBob222
You need to determine k, the rate constant and I would do it this way.
ln(No/N) = kt
No = 10
N = 90
k = solve for this
t = 5 days.

Then knowing k, redo
ln(No/N) = kt
No = 100
N = Solve for this.
k from above
t = 20 days
11 years ago
Anonymous
How
9 years ago

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