Asked by Alice
A radioactive substance decays from 2.0kg to 1.6kg in 156 days.
How much will be left after 201 days?
How much will be left after 201 days?
Answers
Answered by
Elena
N₁=N₀exp(-λt₁)
N₁/N₀ = exp(-λt₁)
ln(N₀/N₁) =λt₁
λ = ln(N₀/N₁)/t₁=
=ln(2/1.6)/156=0.223/156 (day⁻¹)
N₂=N₀exp(-λt₂) =
=2•exp(-0.223•201/156)=2•0.75 =1.5 kg
N₁/N₀ = exp(-λt₁)
ln(N₀/N₁) =λt₁
λ = ln(N₀/N₁)/t₁=
=ln(2/1.6)/156=0.223/156 (day⁻¹)
N₂=N₀exp(-λt₂) =
=2•exp(-0.223•201/156)=2•0.75 =1.5 kg
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.