Asked by Sammantha Avants
A radioactive substance decays at a rate of y = ae^-0.1483t, where t in in hours. Find the half-life of the substance.
How do I solve this problem if I am only given the constant.
How do I solve this problem if I am only given the constant.
Answers
Answered by
Reiny
so you want:
(1/2)a = ae^(-.1483t)
.5 = e^(-.1486t)
take ln of both sides and use rules of logs
-.1486t = ln .5
t = ln .5/-.1486 = appr 4.66 hours
(1/2)a = ae^(-.1483t)
.5 = e^(-.1486t)
take ln of both sides and use rules of logs
-.1486t = ln .5
t = ln .5/-.1486 = appr 4.66 hours
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