Asked by elizabeth
A theater has 30 seats in the first row, 33 seats in the second row, 36 seats in the third row, and so on in the same increasing pattern. If the theater has 15 rows of seats, how many seats are in the theater?
Answers
Answered by
Bosnian
If the initial term of an arithmetic progression is a1 and the common difference of successive members is d, then the nth term of the sequence (an is given by:
an = a1 + ( n - 1 ) * d
This sum :
S = n * [ 2 a1 + ( n - 1 ) * d ] / 2
In this case :
a1 = 30
d = 3
n = 15
S = n * [ 2 a1 + ( n - 1 ) * d ] / 2
S = 15 * [ 2 * 30 + ( 15 - 1 ) * 3 ] / 2 =
15 * ( 60 + 14 * 3 ) / 2 =
15 * ( 60 + 42 ) / 2 =
15 * 102 / 2 = 1530 / 2 = 765
765 seats
an = a1 + ( n - 1 ) * d
This sum :
S = n * [ 2 a1 + ( n - 1 ) * d ] / 2
In this case :
a1 = 30
d = 3
n = 15
S = n * [ 2 a1 + ( n - 1 ) * d ] / 2
S = 15 * [ 2 * 30 + ( 15 - 1 ) * 3 ] / 2 =
15 * ( 60 + 14 * 3 ) / 2 =
15 * ( 60 + 42 ) / 2 =
15 * 102 / 2 = 1530 / 2 = 765
765 seats
Answered by
paschal
how do you round to the nearest gram
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