Asked by Elizabeth
A theater contains 441 seats and the ticket prices for a recent play were $45 for adults and $21 for children. if the total proceeds were 13,797 for a sold out matinee, how many of each type of ticket were sold?.
Answers
Answered by
Bosnian
a = Number of adults
c = Number of children
Total numbers of spectator = 441
a + c = 441
Total proceeds = 13,797 $
a * 45 $ + c * 21 $ = 13,797 $
Now you must solve system of two equation :
a + c = 441
45 a + 21 c = 13,797
Try it.
The solutions are :
a = 189
c = 252
Proof :
a * 45 $ + c * 21 $ =
189 * 45 $ + 252 * 21 $ =
8,505 $ + 5,292 $ = 13,797 $
c = Number of children
Total numbers of spectator = 441
a + c = 441
Total proceeds = 13,797 $
a * 45 $ + c * 21 $ = 13,797 $
Now you must solve system of two equation :
a + c = 441
45 a + 21 c = 13,797
Try it.
The solutions are :
a = 189
c = 252
Proof :
a * 45 $ + c * 21 $ =
189 * 45 $ + 252 * 21 $ =
8,505 $ + 5,292 $ = 13,797 $
Answered by
BOB
WHY DO YOU PUT THE DOLLAR SIGN AFTER THE MONEY... THATS DUMB
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