Asked by nitesh srivastav
A copper ball is dropped from a vartical height 1200m.if the initial temptature of copper ball at the height is 12 degree celsius,what is its temperature on reaching the ground? Assume all its kinetic energy changes to heat energy and specific heat capacity of copper is 400 joule/kilogram degree celsius and g=10m/sec^2.
Answers
Answered by
bobpursley
PEchanbe=heatadded
mgh=m c *(tf-ti)
solve for tfinal tf
tf=g*h/c + ti
It never ceases to amaze me when folks use g=10m/s^2. Nowhere on Earth is it that value. Do they think students are imbeciles and can't use 9.8?
mgh=m c *(tf-ti)
solve for tfinal tf
tf=g*h/c + ti
It never ceases to amaze me when folks use g=10m/s^2. Nowhere on Earth is it that value. Do they think students are imbeciles and can't use 9.8?
Answered by
Damon
The same folks say that pi is 3.00 :)
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