Asked by taryn
A 52.0 g ball of copper has a net charge of 2.1 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)
Answers
Answered by
bobpursley
number electrons removed=2.1microC*/charge on one electron
original number elecrons:
number moles*avagrado's number*29
fraction=removed/original
original number elecrons:
number moles*avagrado's number*29
fraction=removed/original
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