Ask a New Question

Asked by taryn

A 52.0 g ball of copper has a net charge of 2.1 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)
12 years ago

Answers

Answered by bobpursley
number electrons removed=2.1microC*/charge on one electron

original number elecrons:

number moles*avagrado's number*29

fraction=removed/original
12 years ago

Related Questions

A copper ball has a mass of 1kg.Calculate the radius of the ball,given that the density of copper is... A 2.0 mm diameter copper ball is charged to +42 nC. What fraction of its electrons have been removed... A copper ball 2 cm in radius is heated in a furnace to 400 degree celsius. if its emissivity is 0.3,... A copper ball is dropped from a vartical height 1200m.if the initial temptature of copper ball at th... A piece of copper of ball of mass 20g is placed in a copper calorimeter of mass 60g containing 50g o... A piece of copper ball of mass 30grams at 150 degree celcius is placed in a copper calorimeter of ma... A piece of copper ball of mass 20g at 200 degree centigrade is placed in a copper calorimeter of mas... A piece of copper ball at 80 degree Celsius is quickly transferred into a copper calorimeter of mass... What happens when copper ball is heated What happens to the copper ball during heating
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use