Asked by taryn
                A 52.0 g ball of copper has a net charge of 2.1 µC. What fraction of the copper's electrons have been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)
            
            
        Answers
                    Answered by
            bobpursley
            
    number electrons removed=2.1microC*/charge on one electron
original number elecrons:
number moles*avagrado's number*29
fraction=removed/original
    
original number elecrons:
number moles*avagrado's number*29
fraction=removed/original
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.