Asked by Jdreem Thomas

A ball is dropped from the top of a building. If it takes 3.00 s for the ball to hit the street below, how high is the building?

Answers

Answered by L.L
vf = 0
t = 3.00
a = -g
y = ?

y = vft - 1/2at^2
y = 0 - 1/2(-9.80)(3.00)^2
y = 4.40(9.00)
y = 39.6 m

the building is 39.6 m high
Answered by Isabella
44.1 m was the correct answer
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