Question
How many grams of zinc metal are required to produce 2.00 L of hydrogen gas at STP
according to the chemical equation shown below?
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
according to the chemical equation shown below?
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
Answers
Steve
22.4 Mol/L at STP means 44.8 moles of H2
Each mole of Zn produces one mole of H2, so you need 44.8 moles of Zn.
How many grams is that?
Each mole of Zn produces one mole of H2, so you need 44.8 moles of Zn.
How many grams is that?
Matt
Do you mean 44.8L of Zn?
Ryan
when I do m=M*n
I get a really high Number which I don't think is right.
I get a really high Number which I don't think is right.
DrBob222
It isn't. That's 22.4 L/mol and not 22.4 mols/L. So you want 2/22.4 = ? mols H2 produced.
Dave
The answer is 5.83g
David
1 mol of any gas occupies 22.4L of space at STP.
2L of H2 spread in 22.4L of space =2/22= .089molH2
According to the equation, 1 mol H2 is produced from 1 mol of Zn. .089molH2 * 65.38gZn = 5.8gZn
2L of H2 spread in 22.4L of space =2/22= .089molH2
According to the equation, 1 mol H2 is produced from 1 mol of Zn. .089molH2 * 65.38gZn = 5.8gZn