Asked by Ryan

How many grams of zinc metal are required to produce 2.00 L of hydrogen gas at STP
according to the chemical equation shown below?
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
Answered by Steve
22.4 Mol/L at STP means 44.8 moles of H2

Each mole of Zn produces one mole of H2, so you need 44.8 moles of Zn.

How many grams is that?
Answered by Matt
Do you mean 44.8L of Zn?
Answered by Ryan
when I do m=M*n
I get a really high Number which I don't think is right.
Answered by DrBob222
It isn't. That's 22.4 L/mol and not 22.4 mols/L. So you want 2/22.4 = ? mols H2 produced.
Answered by Dave
The answer is 5.83g
Answered by David
1 mol of any gas occupies 22.4L of space at STP.
2L of H2 spread in 22.4L of space =2/22= .089molH2
According to the equation, 1 mol H2 is produced from 1 mol of Zn. .089molH2 * 65.38gZn = 5.8gZn
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