Question

a 2.00g sample of zinc metal is added to a calorimeter containing 150g of nitric acid solution initially at 20.0 degrees celsius . The temperature of the solution increased to 28.0 degrees celsius . Calculate the delta H of the reaction assuming that the specific heat capacity of the solution = 4.18J/g degrees celsius

Answer 1

q = mass x specific heat x delta T.
q = 150 x 4.18 x 8 = ? J which is delta H for the reaction. Most of these problems want delta H/mol or delta H/g but this post asks for neither.