Asked by xx
Exactly .203g of zinc metal is dissolved in dilute HCl(aq) in an ice calorimeter. The heat released melts enough ice to produce a volume change of 0.254mL in the ice water mixture surrounding the reaction vessel. Calculate the enthalpy change per mole of zinc for the reaction:
Zn(s) +HCl(aq)→Zn2+(aq) +H2(G)
Zn(s) +HCl(aq)→Zn2+(aq) +H2(G)
Answers
Answered by
bobpursley
heat for ice melting=254*Hf
Hf=above*molmassZn/.203
Hf=above*molmassZn/.203
Answered by
bobpursley
disregard last line
delta H= heatfor ice melting*molmass/.203
delta H= heatfor ice melting*molmass/.203
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