Exactly .203g of zinc metal is dissolved in dilute HCl(aq) in an ice calorimeter. The heat released melts enough ice to produce a volume change of 0.254mL in the ice water mixture surrounding the reaction vessel. Calculate the enthalpy change per mole of zinc for the reaction:

Question

Exactly .203g of zinc metal is dissolved in dilute HCl(aq) in an ice calorimeter. The heat released melts enough ice to produce a volume change of 0.254mL in the ice water mixture surrounding the reaction vessel. Calculate the enthalpy change per mole of zinc for the reaction: 
Zn(s) +HCl(aq)→Zn2+(aq) +H2(G)

bobpursley · Answer

heat for ice melting=254*Hf Hf=above*molmassZn/.203

bobpursley · Answer

disregard last line delta H= heatfor ice melting*molmass/.203