Question

a ball of mass m is thrown vertically upwards with Vo= 10j m/s. Study nature of motion

Answer 1

g is about 9.81 m/s^2 down

F = m a
here F = -9.81 m
so m a = -9.81 m
a = -9.81 m/s^2 or g downward

v = speed up

v = Vi - a t = 10 - 9.81 t
so v decreases proportional to time until it reaches 0 at the top of its flight. Then it starts down.
that time is t = 10/9.81

h = height = Hi + Vi t - (1/2) 9.81 t^2
for example at the top
h = Hi + 10 (10/9.81) - (1/2)(9.81)(10/9.81)^2

h= Hi +(1/2)(9.81)Vi^2