Question
a ball of mass 4kg is thrown vertically upwards with a velocity of 40m/s.Find
a-maximum height
b-height after 3 seconds
c-time of flight
a-maximum height
b-height after 3 seconds
c-time of flight
Answers
drwls
(a) Maximum height H is where the potential energy M g H equals the initial kinetic energy, (M/2)Vo^2.
Thus H = Vo^2/(2g)
(b) y(t) = Vo*t - (g/2) t6^2
Plug in t = 3.
(c) Twice as long as it takes for velocity to go from Vo to 0.
Thus H = Vo^2/(2g)
(b) y(t) = Vo*t - (g/2) t6^2
Plug in t = 3.
(c) Twice as long as it takes for velocity to go from Vo to 0.