Question

A 0.255 kg ball was thrown vertically upward from a bridge 10.3 meters above the ground with an initial velocity if 31.7 meters/second. Calculate the balls velocity when it hits the water.
Gravitational potential energy becomes increased kinetic energy.

MgH = (M/2)[Vfinal^2 - Vinitial^2]

Vfinal^2 = 2gH + Vinitial^2
= 100.9 + 1004.9 m^2/s^2
= 110.6 m^2/s^2
Vfinal = 33.3 m/s

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