Question
the sides of a rectangle are given in centimeters up length 4x+3 down length x+ 6y,left width 3x+1 right width 4x-y. find x and y and area of the rectangle .solution 4x+3=x+6y . y=3x+3÷6 also 4x-y=3x+1.x=y+1
Answers
Jai
Yes that's right. You have to equate the expressions for widths and for the lengths, since left and right widths (and lengths) have the same dimensions.
You may rewrite the equation for y=3x+3÷6 as
y = (3x + 3)/6
And now you have an expression for y, we can substitute it to the other equation you got:
x = y + 1
x = (3x + 3)/6 + 1
And solve for x. After you got the value of x, you can solve for y.
You may rewrite the equation for y=3x+3÷6 as
y = (3x + 3)/6
And now you have an expression for y, we can substitute it to the other equation you got:
x = y + 1
x = (3x + 3)/6 + 1
And solve for x. After you got the value of x, you can solve for y.
khadar naasir cabdi
I do not answer
Irene
I know this was given yearssss ago, but thanks!!!!! It helped a lot today
Charles
Amazing
Joy
I don't understand
mary Adaeze
y=3x+3÷6 as y=(3x+3)/6
substitute the equation
x=y+1
x=(3x+3)/6 +1
least i can try
substitute the equation
x=y+1
x=(3x+3)/6 +1
least i can try
Ejiogu Paulina Chinyere
Area=L × w=4x+3=x+6y
y=4x_3+3+6
y=3+3+6
y=6+6
y=12.
L×w=4x_y =3x+1
X=4x_3x+1+1
1x=2
x=2
y=4x_3+3+6
y=3+3+6
y=6+6
y=12.
L×w=4x_y =3x+1
X=4x_3x+1+1
1x=2
x=2
Michael
I don't understand
Sekinat
I did not understand
Scholastica Goodness
4x-y=x+6y
4x+3=x+6y
X=3,Y=2
4x+3=x+6y
X=3,Y=2
Bot
I see. Can you please show me how you got these values for x and y? It will be easier for me to help you understand.
Scholastica Goodness
I got it by doing 4(3)+3=15
3+6(2)=15
=150cm
3+6(2)=15
=150cm
Bot
I think you are confusing the solution for the values of x and y with the solution for the area of the rectangle.
Let's go back to the equations you derived:
- Length: 4x + 3 = x + 6y
- Width: 3x + 1 = 4x - y
From the first equation, we can solve for x in terms of y:
4x + 3 = x + 6y
3x = 6y - 3
x = 2y - 1
Substituting this expression for x into the second equation:
3(2y-1) + 1 = 4(2y-1) - y
6y - 2 + 1 = 8y - 4 - y
y = 3
So, we have found that y = 3. Now we can substitute this value back into either one of the equations to find the corresponding value of x:
4x + 3 = x + 6y
4x + 3 = x + 6(3)
4x + 3 = x + 18
3x = 15
x = 5
Therefore, we have found that x = 5 and y = 3.
Now, we can calculate the area of the rectangle:
Area = (4x + 3)(3x + 1)
Area = (4(5) + 3)(3(5) + 1)
Area = (23)(16)
Area = 368 cm^2
I hope this clarifies the solution for you!
Let's go back to the equations you derived:
- Length: 4x + 3 = x + 6y
- Width: 3x + 1 = 4x - y
From the first equation, we can solve for x in terms of y:
4x + 3 = x + 6y
3x = 6y - 3
x = 2y - 1
Substituting this expression for x into the second equation:
3(2y-1) + 1 = 4(2y-1) - y
6y - 2 + 1 = 8y - 4 - y
y = 3
So, we have found that y = 3. Now we can substitute this value back into either one of the equations to find the corresponding value of x:
4x + 3 = x + 6y
4x + 3 = x + 6(3)
4x + 3 = x + 18
3x = 15
x = 5
Therefore, we have found that x = 5 and y = 3.
Now, we can calculate the area of the rectangle:
Area = (4x + 3)(3x + 1)
Area = (4(5) + 3)(3(5) + 1)
Area = (23)(16)
Area = 368 cm^2
I hope this clarifies the solution for you!