With the given information below, write the standard form equation for the parabola.

1.) Vertex: (-1,2)
Focus(-1,0)

2.) Vertex: (-2,1)
Directrix x=1

1 answer

the parabola is vertical, and opens downwards
standard form x^2 = 4py
but vertex is (-1,2)
(x+1)^2 = 4p(y-2)
but p = -2
(x+1)^2 = -8(y-2)
(x+1)^2 = -8y + 16
8y = -(x+1)^2 + 16
y = (-1/8)(x+1)^2 - 2

for the 2nd , use y^2 = 4px and follow the above steps
Similar Questions
  1. Can you please help me with the below question:The vertex of a parabola is located at (-12, -1). The parabola also passes
    1. answers icon 1 answer
    1. answers icon 3 answers
  2. y=−3x2−4x+1(a) Write the equation of the parabola in standard form (b) Identify the vertex of the parabola C)Is the vertex a
    1. answers icon 4 answers
    1. answers icon 2 answers
more similar questions