Question

Can you please help me with the below question:

The vertex of a parabola is located at (-12, -1). The parabola also passes through the point (-10, 5).
Write the equation of this parabola in both vertex form and standard form.
Vertex form:
Standard form:

Thank you

Answer 1

using the vertex:
y = a(x+12)^2 - 1
but (-10,5) lies on it, so ...
5= a(2^2) - 1
6 = 4a
a = 3/2

y = (3/2)(x + 12)^2 - 1

expand to get the other form