Asked by Emily
Carbon monoxide and hydrogen react according to the equation:
CO(g) + 3H2(g) CH4(g) + H2O
When 1.00 mol CO and 3.00 mol H2 are placed in a 1L flask at 1200K and allowed to come to equilibrium, the reaction mixture is found to contain 0.387 mol H2O. What is the molar composition of the equilibrium mixture?
CO(g) + 3H2(g) CH4(g) + H2O
When 1.00 mol CO and 3.00 mol H2 are placed in a 1L flask at 1200K and allowed to come to equilibrium, the reaction mixture is found to contain 0.387 mol H2O. What is the molar composition of the equilibrium mixture?
Answers
Answered by
Anonymous
Well, if you have .387mol steam, then you used .387 mol CO, and 3*.387 mole H2. To find out the molar concentration of CO and H2, subtract what was used from the initial. The amount of CH4 of course is the same as H2O.
Answered by
sam
Moles of h2o driven off
And convert grams 0.85 to moles
And convert grams 0.85 to moles
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