Question
Carbon monoxide is a gas at 0 degree Celsius and a pressure of 1.51x10^5 Pa. It is a diatomic gas, each of its molecules consisting of one carbon atom (atomic mass = 12.o u) and one oxygen atom (atomic mass = 16.0 u). Assuming that carbon monoxide is an ideal gas, calculate its density p.
Answers
P V = n R T
find n in V= 1 meter^3, then we will find molar mass later
1.51*10^5 * 1 = n *8.31 (273+0)
n = 66.6 mols
now a mol of CO has mass 12+16 = 28 grams = .028 Kg
so we have
.028 * 66 = 1.85 kg /m^3
find n in V= 1 meter^3, then we will find molar mass later
1.51*10^5 * 1 = n *8.31 (273+0)
n = 66.6 mols
now a mol of CO has mass 12+16 = 28 grams = .028 Kg
so we have
.028 * 66 = 1.85 kg /m^3
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