Asked by Nino

complete the square y^2+6y-3x+3=0
Answered by Damon
y^2 + 6 y = 3 x - 3

y^2 + 6 y + 9 = 3 x + 6

(y+3)^2 = 3 x + 6

(y+3)^2 = 3 (x+2)

vertex at (-2,-3) open to right
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