Asked by Tim
complete the square 16x-12y=4y^2+1
Answers
Answered by
Steve
16x = 4y^2 + 12y + 1
16x = 4(y^2 + 3y) + 1
16x = 4(y^2 + 3y + 9/4) + 1 - 4(9/4)
16x = 4(y + 3/2)^2 - 3
x = 1/4 (y + 3/2)^2 - 3/16
16x = 4(y^2 + 3y) + 1
16x = 4(y^2 + 3y + 9/4) + 1 - 4(9/4)
16x = 4(y + 3/2)^2 - 3
x = 1/4 (y + 3/2)^2 - 3/16
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