Asked by luckybee
complete the square
2x^2-4x-1=0
2x^2-4x-1=0
Answers
Answered by
Reiny
solve by completing the square ??
first divide by 2 and move the constant to the right ...
x^2 - 2x = 1
add 1 to both sides
x^2 - 2x + 1 = 1 + 1
(x-1)^2 = 2
x-1 = ± √2
x = 1 ± √2
first divide by 2 and move the constant to the right ...
x^2 - 2x = 1
add 1 to both sides
x^2 - 2x + 1 = 1 + 1
(x-1)^2 = 2
x-1 = ± √2
x = 1 ± √2
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