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Asked by
Mimi
complete the square
X2-4x+y2+6y=0
Show work please
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Answered by
R_scott
divide the 1st order terms' coefficients by 2, and square the results
x^2 - 4 x + (-4/2)^2 + y^2 + 6 y + (6/2)^2 = (-2)^2 + 3^2
(x - 2)^2 + (y + 3)^2 = 13
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