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Asked by Mimi

complete the square
X2-4x+y2+6y=0

Show work please
6 years ago

Answers

Answered by R_scott
divide the 1st order terms' coefficients by 2, and square the results

x^2 - 4 x + (-4/2)^2 + y^2 + 6 y + (6/2)^2 = (-2)^2 + 3^2

(x - 2)^2 + (y + 3)^2 = 13
6 years ago

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