Asked by Ashalalalala
Complete the square
2y^2-y-6=0
2y^2-y-6=0
Answers
Answered by
bobpursley
2(y^2-1/2 y -3)
add and subtract (1/4)^2
2(y^2-1/2 y +1/16 -3-1/16)=0
2(y-1/4)^2=6 1/8
(y-1/4)^2= 3 1/16=49/16
add and subtract (1/4)^2
2(y^2-1/2 y +1/16 -3-1/16)=0
2(y-1/4)^2=6 1/8
(y-1/4)^2= 3 1/16=49/16
Answered by
drwls
The subject is algebra, and it is not college level.
Start with
y^2 -y/2 = 3
To make the left a perfect square, add 1/16 to both sides.
y^2 - y/2 + 1/16 = 49/16
[y - (1/4)]^2 = 49/16
y - 1/4 = + or - 7/4
Add 1/4 to both sides for the two answers
Start with
y^2 -y/2 = 3
To make the left a perfect square, add 1/16 to both sides.
y^2 - y/2 + 1/16 = 49/16
[y - (1/4)]^2 = 49/16
y - 1/4 = + or - 7/4
Add 1/4 to both sides for the two answers
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