Asked by reneae
complete the square
x^2-4x+y^2+6y=0
x^2-4x+y^2+6y=0
Answers
Answered by
oobleck
x^2-4x+y^2+6y=0
x^2-4x + y^2+6y = 0
x^2-4x+4 + y^2+6y+9 = 4+9
(x-2)^2 + (y+3)^2 = 13
x^2-4x + y^2+6y = 0
x^2-4x+4 + y^2+6y+9 = 4+9
(x-2)^2 + (y+3)^2 = 13
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