Question
A particle moves along the X axis with the acceleration a(t)=12t-6. If v(0)=3, find the total distance the particle traveled from t=0 to t=2.
Please help
Please help
Answers
Steve
a = 12t-6
v = 6t^2-6t+c
v(0)=3, so c=3, and
v = 6t^2-6t+3
s = 2t^3-3t^2+3t+c
Since we assume zero distance at t=0, c=0.
s(2) = 2*8 - 3*4 + 3*2 = 10
v = 6t^2-6t+c
v(0)=3, so c=3, and
v = 6t^2-6t+3
s = 2t^3-3t^2+3t+c
Since we assume zero distance at t=0, c=0.
s(2) = 2*8 - 3*4 + 3*2 = 10