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Lynds
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A particle moves along the X axis with the acceleration a(t)=12t-6. If v(0)=3, find the total distance the particle traveled
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If y= e^x - e^-x / e^x + e^-x , then y'=
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I know the correct answer is 4 / (e^x + e^-x)^2
I took the derivative and got Y'= (e^x+ e^-x) ( e^x + e^-x) - (e^x + e^-x) (e^x - e^-x)/ (e^x + e^-x)^2