Asked by Ekingdeft
I was aked to prove that (a - b)^2 = (a + b)^2 - 4ab
Answers
Answered by
Reiny
LS = (a-b)^2
= a^2 - 2ab + b^2
RS = (a+b)^2 - 4ab
= a^2 + 2ab + b^2 - 4ab
= a^2 - 2ab + b^2
= LS
Q.E.D.
or
(quid est demonstrata)
(Thus it has been proven)
= a^2 - 2ab + b^2
RS = (a+b)^2 - 4ab
= a^2 + 2ab + b^2 - 4ab
= a^2 - 2ab + b^2
= LS
Q.E.D.
or
(quid est demonstrata)
(Thus it has been proven)
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