Question

Iron 3 hydroxide reacts with acetic acid to form iron 3 acetate and water. If 45.4g of water are formed,what mass of iron 3 acetate will be produced?
•Fe(OH)3+3HC2H3O2--->Fe(C2H3O2)+3H2O

45.4H2O( ? Fe(C2H3O))
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( ? H2O)

Answer 1

45.4g of H2O*(1 mole/18.00g)=moles of H2O

moles of H2O*(moles of Fe(C2H3O2)/3 mole of H2O)=moles of Fe(C2H3O2)

moles of Fe(C2H3O2)*(232.98 g/1 mole of moles of Fe(C2H3O2))= g of Fe(C2H3O2)

Answer 2

You made a typo on the formula for iron (III) acetate.
•Fe(OH)3 + 3HC2H3O2 --> Fe(C2H3O2)3 + 3H2O

mols water formed = grams/molar mass = ?
Convert to mols iron(III) acetate using the coefficients in the balanced equation. That will be
? mols H2O x (1 mol Fe(Ac)3/3 mol H2O) = ?mols H2O x 1/3 = x mols Fe(Ac)3.
Then convert that to grams. g = mols x molar mass = ?