Asked by tur
Iron (iii) hydroxide reacts with acetic acid to form iron (iii) acetate and water. If 45.4 grams of water are formed, how many grams of iron (iii) acetate will be produced?
Fe(OH)3 + 3HC2H2O2 --> Fe(C2H3O2)3 + 3H2O
Fe(OH)3 + 3HC2H2O2 --> Fe(C2H3O2)3 + 3H2O
Answers
Answered by
DrBob222
Fe(OH)3 + 3HC2H2O2 --> Fe(C2H3O2)3 + 3H2O
How many mols in 45.4 g H2O. mols = g/molar mass
= 45.4/18 = 2.5 but that's an estimate. You should redo all of these calculations. Now use the coefficients in the equation.
Then 2.5 mols H2O x ( 1 mol Fe(C2H3O2)3/3 mols H2O) = mols Fe(C2H3O2)3.
Convert that to grams with the above formula.
How many mols in 45.4 g H2O. mols = g/molar mass
= 45.4/18 = 2.5 but that's an estimate. You should redo all of these calculations. Now use the coefficients in the equation.
Then 2.5 mols H2O x ( 1 mol Fe(C2H3O2)3/3 mols H2O) = mols Fe(C2H3O2)3.
Convert that to grams with the above formula.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.