Asked by TayB
Find an expression for the function whose graph is the given curve.
The top half of the circle x^2+(y-4)^2=4
The top half of the circle x^2+(y-4)^2=4
Answers
Answered by
Reiny
(y - 4)^2 = 4 - x^2
y - 4 = ±√(4 - x^2)
but we only want the top part, so
y - 4 = +√(4 - x^2)
y = √(4-x^2) + 4
Wolfram verification:
http://www.wolframalpha.com/input/?i=plot+y+%3D+%E2%88%9A%284-x%5E2%29+%2B+4+from+-2+to+2
y - 4 = ±√(4 - x^2)
but we only want the top part, so
y - 4 = +√(4 - x^2)
y = √(4-x^2) + 4
Wolfram verification:
http://www.wolframalpha.com/input/?i=plot+y+%3D+%E2%88%9A%284-x%5E2%29+%2B+4+from+-2+to+2
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