Asked by KC
Find an expression for the function. Top half of the circle: x^2+(y-2)^2=4.
Answers
Answered by
Steve
(y-2)^2 = 4 - x^2
y-2 = sqrt(4-x^2)
y = sqrt(4-x^2) + 2
y-2 = sqrt(4-x^2)
y = sqrt(4-x^2) + 2
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