Asked by scarlette. . .need help asap
find the sum of p+m if the function
g(x)= p(x^2-m)/(x+2)(x+5)has a horizontal asymptote at y=5 and a hole at x=-2
g(x)= p(x^2-m)/(x+2)(x+5)has a horizontal asymptote at y=5 and a hole at x=-2
Answers
Answered by
Steve
we know that at large x,
g(x) =~ 5, so p = 5, giving us
g(x) = 5(x^2 - m)/(x+2)(x+5)
A hole at x = -2 means that the numerator is divisible by (x+2) so that
g(x) = 5(x+2)(x-2)/(x+2)(x+5)
making m = 4
p+m = 9
g(x) =~ 5, so p = 5, giving us
g(x) = 5(x^2 - m)/(x+2)(x+5)
A hole at x = -2 means that the numerator is divisible by (x+2) so that
g(x) = 5(x+2)(x-2)/(x+2)(x+5)
making m = 4
p+m = 9