Asked by Nick
What is the equilibrium molarity of chloride if 19.6g of CaCl2 (110.984g/mol) is dissolved in water and diluted to 0.500L?
Answers
Answered by
Anonymous
Answer contains three significant figures.
Molarity=moles/Volume (L)
Calculate moles of CaCl2, followed by moles of Cl2:
[19.6g*(1 mole/110.984g)]=-moles of CaCl2
moles of CaCl2*(2 moles of Cl/1 moles of CaCl2)= moles of Cl
moles of Cl/0.500L= molarity of Cl
Molarity=moles/Volume (L)
Calculate moles of CaCl2, followed by moles of Cl2:
[19.6g*(1 mole/110.984g)]=-moles of CaCl2
moles of CaCl2*(2 moles of Cl/1 moles of CaCl2)= moles of Cl
moles of Cl/0.500L= molarity of Cl
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