Question

For the equilibrium below at 400 K, Kc = 7.0.
Br2(g) + Cl2(g) equilibrium reaction arrow 2 BrCl(g)
If 0.85 mol of Br2 and 0.85 mol Cl2 are introduced into a 2.0 L-container at 400. K, what will be the equilibrium concentrations of Br2, Cl2 and BrCl?
I tried to set it up and everytime i work it out i get the wrong answer

Answer 1

Why don't you show your work and let us find the error?
M = 0.85 mols/2L = 0.425M
........Br2 + Cl2 ==> 2BrCl
I.....0.425..0.425.....0
C.......-x.....-x......2x
E.....0.425-x.0.425-x..2x

Go from there.

Answer 2

ohh I converted from grams to molariry instead of from mols i'll try it with the new calculations.