Asked by Hannah
                Neutralization Reaction Molarity Calculations:
For example: What is the molarity of a Ca(OH)2 solution if .032 L of the solution is exactly neutralized by .015 of a 0.56 M HCl?
How do I solve- I am unsure where to begin.
            
        For example: What is the molarity of a Ca(OH)2 solution if .032 L of the solution is exactly neutralized by .015 of a 0.56 M HCl?
How do I solve- I am unsure where to begin.
Answers
                    Answered by
            bobpursley
            
    Balance the equation:
Ca(OH)2 + 2HCl >> CaCl2 + 2H20
ok, it takes two moles of HCl for each mole of Calcium hydroxide.
moles Ca(OH)=Molarity*volume and you don't know M
moles HCl= molarity*Volume=.56*.015
so, the 2* molesCa(OH)2= moleHCL
and you can then find molarity of the calcium hydroxide.
    
Ca(OH)2 + 2HCl >> CaCl2 + 2H20
ok, it takes two moles of HCl for each mole of Calcium hydroxide.
moles Ca(OH)=Molarity*volume and you don't know M
moles HCl= molarity*Volume=.56*.015
so, the 2* molesCa(OH)2= moleHCL
and you can then find molarity of the calcium hydroxide.
                    Answered by
            Hannah
            
    Thanks!
    
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