Asked by Hannah
Neutralization Reaction Molarity Calculations:
For example: What is the molarity of a Ca(OH)2 solution if .032 L of the solution is exactly neutralized by .015 of a 0.56 M HCl?
How do I solve- I am unsure where to begin.
For example: What is the molarity of a Ca(OH)2 solution if .032 L of the solution is exactly neutralized by .015 of a 0.56 M HCl?
How do I solve- I am unsure where to begin.
Answers
Answered by
bobpursley
Balance the equation:
Ca(OH)2 + 2HCl >> CaCl2 + 2H20
ok, it takes two moles of HCl for each mole of Calcium hydroxide.
moles Ca(OH)=Molarity*volume and you don't know M
moles HCl= molarity*Volume=.56*.015
so, the 2* molesCa(OH)2= moleHCL
and you can then find molarity of the calcium hydroxide.
Ca(OH)2 + 2HCl >> CaCl2 + 2H20
ok, it takes two moles of HCl for each mole of Calcium hydroxide.
moles Ca(OH)=Molarity*volume and you don't know M
moles HCl= molarity*Volume=.56*.015
so, the 2* molesCa(OH)2= moleHCL
and you can then find molarity of the calcium hydroxide.
Answered by
Hannah
Thanks!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.