Asked by Radio Active Wear

For the neutralization reaction involving HNO3 and Ca(OH)2, how many liters of 1.55 M HNO3 are needed to react with 45.8 mL of a 4.66 M Ca(OH)2 solution?

1. 0.137 L
2. 0.0343 L
3. 0.275 L
4. 1.32 L
5. 0.662 L
6. 0.330 L
Answered by DrBob222
2HNO3 + Ca(OH)2 ==> Ca(NO3)2 + 2H2O
mols Ca(OH)2 = M x L = ?
Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols HNO3.
Then M HNO3 = mols HNO3/LHNO3. You have mols and M, solve for L.
Answered by Radio Active Wear
Thank you so much!!!
Answered by Guy who dislikes UT Quest
If you're just trying to finish UT like this.
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