Question
For the neutralization reaction involving HNO3 and Ca(OH)2, how many liters of 1.55 M HNO3 are needed to react with 45.8 mL of a 4.66 M Ca(OH)2 solution?
1. 0.137 L
2. 0.0343 L
3. 0.275 L
4. 1.32 L
5. 0.662 L
6. 0.330 L
1. 0.137 L
2. 0.0343 L
3. 0.275 L
4. 1.32 L
5. 0.662 L
6. 0.330 L
Answers
2HNO3 + Ca(OH)2 ==> Ca(NO3)2 + 2H2O
mols Ca(OH)2 = M x L = ?
Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols HNO3.
Then M HNO3 = mols HNO3/LHNO3. You have mols and M, solve for L.
mols Ca(OH)2 = M x L = ?
Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols HNO3.
Then M HNO3 = mols HNO3/LHNO3. You have mols and M, solve for L.
Thank you so much!!!
If you're just trying to finish UT like this.
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