Asked by Tasha
In the following acid—base neutralization reaction
HNO3(aq)+ KOH(aq) ----KNO3(aq) + H2O (I)
What is the molarity (M) of an HNO3 solution if 50.0 ml is needed to react with 25.0 ml of 0.150M KOH solution?
HNO3(aq)+ KOH(aq) ----KNO3(aq) + H2O (I)
What is the molarity (M) of an HNO3 solution if 50.0 ml is needed to react with 25.0 ml of 0.150M KOH solution?
Answers
Answered by
DrBob222
mols KOH = M x L = ?
Look at the equation; it is 1:1, therefore, mols HNO3 = mols KOH.
M HNO3 = mols HNO3/L HNO3.
Look at the equation; it is 1:1, therefore, mols HNO3 = mols KOH.
M HNO3 = mols HNO3/L HNO3.
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