Asked by Anonymous
A 2.0 kg mass starts from rest and slides down an inclined plane 7.9 ✕ 10-1 m long in 0.64 s. What net force is acting on the mass along the incline?
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Answers
Answered by
Henry
d = 0.5a*t^2
d = 0.79 m.
t = 0.64 s.
Solve for a.
F = m*a
d = 0.79 m.
t = 0.64 s.
Solve for a.
F = m*a
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