Question

If a car starts from rest and accelerates at 6.0 m/sec2 for 6.0 seconds. how far did it travel and how fast was it moving at the end of the 6.0 seconds

Answer 1

Assemble the data first:

Initial velocity = vi = 0m/s
Acceleration = a = 6m/s2
Time = t = 6s
Distance = S = ??
Final velocity = vf = ??

Now using equations of motion:

FOR DISTANCE:

Since,
S = vit + 1/2at2
Put in the values,

S = 0*6 + 1/2*6*(6)2
S = 0 + 1/2*6*36
S - 108m

FOR FINAL VELOCITY

Both remaining equations of motion can be used.

Method # 01:

Using equation;
2aS = vf2 - vi2
2*6*108 = vf2-0
1296 = vf2
vf2 = 1296
vf = square root of 1296
vf = 36m/s

OR

Methos # 02:

Using equation;
vf = vi + at
vf = 0 + 6*6
vf = 36m/s.

Hope it helps.