Asked by Sally
A CD-Rom starts from rest and undergoes uniform angular acceleration until it reaches 26,000 rpm in 0.25 s. Through what angle does it rotate during this time?
Answers
Answered by
Elena
f= 26,000 rpm=26000/3600=7.2 rev/s
2πf = εt
ε = 2πf/t =2π•7.2/0.25 =176 rad/s²
φ = εt²/2 = 176•(0.25)²/2 =5.5 rad
2πf = εt
ε = 2πf/t =2π•7.2/0.25 =176 rad/s²
φ = εt²/2 = 176•(0.25)²/2 =5.5 rad
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