Asked by Sarah

Find all points on the graph of f(x)=-x^3+3x^2-2 where there is a horizontal tangent line.
Answered by bobpursley
f'=0=2x^2+6x

= 2x(x+3) so at x=0, x=-3, the tangent is horizontal.
Answered by Damon
since it is a cubic, there will presumably be two

f' = 0 = 3 x^2 + 6 x = 3x ( x+2)
x = 0 and x = -2
you find f(x) there
Answered by Sarah
Would the points be (0,-2) and -2, 18) when I plug them into f(x)?
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