Asked by Michael
Find the points on the graph of y = 1/x where the graph is parallel to the line 4x + 9y = 3.
Answers
Answered by
drwls
The slope of the straight line
4x + 9y = 3 is
-9/4.
You want points on the line y = 1/x where
dy/dx = -9/4. Therefore solve
-1/x^2 = -9/4
x^2 = 4/9
x = +2/3 and -2/3.
At those points, y = 3/2 and -3/2, respectively.
Therefore there are two points on the curve that satisfy the slope requirement:
(2/3, 3/2) and (-2/3, -3/2)
4x + 9y = 3 is
-9/4.
You want points on the line y = 1/x where
dy/dx = -9/4. Therefore solve
-1/x^2 = -9/4
x^2 = 4/9
x = +2/3 and -2/3.
At those points, y = 3/2 and -3/2, respectively.
Therefore there are two points on the curve that satisfy the slope requirement:
(2/3, 3/2) and (-2/3, -3/2)
Answered by
Andy
Would the slope not be -4/9?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.