Ask a New Question

Question

Find the points on the graph y = -x^3 + 6x^2 at which the tangent line is horizontal.
I found -x^2 + 4 = 0
are the points [4,32]
8 years ago

Answers

bobpursley
y'=0=-3x^2+12x or
x(-x+4)=0
so the x points are 0,4
so the graph points are
(0,0) and (4,32)
8 years ago

Related Questions

Find the points on the graph of y = (x+1)/ (x+2) where the tangent line is parallel to the line x... Find all points on the graph of f(x)=xe^x at which the tangent line is parallel to the line y-3x=4.... Find the points on the graph of y = 1/x where the graph is parallel to the line 4x + 9y = 3. Find the points on the graph of the following function where the slope of the tangent line is equal... Find all points on the graph of y=1/4x^4+2/3x^3-5/2x^2+6x+7 where the slop of the tangent lins is 12... Find all points of the graph of y=7x^2+7x whose tangent lines are perpendicular to the line -49y=x find two points on the graph other than the vertex and x intercept of f(x)=-(x+5)^2 find all points on the graph of f at which the tangent line is horizontal a) f(x)=(x+1)/(x^2+3) b)... Find all points on the graph of the function f(x)= 2sin(x)+sin^2(x) at which the tangent line is ho... find the points where the graph of the function have horizontal tangents f(x) = 4x^2 + 6x - 5
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use