we see that y^2 = 17-4x, so
2x^2 + 5(17-4x) = 53
2x^2 - 29x + 32 = 0
2(x-2)(x-8) = 0
...
Solving Quadratic Systems
2x^2+5y^2=53
4x+y^2=17
Please show work I'm having trouble solving it.
4 answers
Where did you get 29 from?
And where did you get 32 from?
4666 silly willy 420
2 answers