Asked by Genesis
Solving Quadratic Systems
x^2+y^2=10
2x+y=4
Please show work I need to know how to do it
x^2+y^2=10
2x+y=4
Please show work I need to know how to do it
Answers
Answered by
Steve
since we know y = 4-2x, use that:
x^2+(4-2x)^2 = 10
5x^2 - 16x + 6 = 0
Now it's just the normal routine for solving a quadratic equation.
x^2+(4-2x)^2 = 10
5x^2 - 16x + 6 = 0
Now it's just the normal routine for solving a quadratic equation.
Answered by
Genesis
how do I solve the answer
Answered by
Reiny
from the type of problem that you posted, you surely MUST know how to solve quadratic equations.
Steve took you as far as 5x^2 - 16x + 6 = 0 and made the same assumption I made.
I suggest using the quadratic formula.
(you will get two irrational answers)
Steve took you as far as 5x^2 - 16x + 6 = 0 and made the same assumption I made.
I suggest using the quadratic formula.
(you will get two irrational answers)
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